This math puzzle is one of the most loved by Internet users. The question is about a deck of cards in which a few cards are missing. The challenge is to find out how many cards are in the pack and how many are missing from it. Trivia question: “A small number of cards were missing from a complete package. If I deal to four people, there are three cards left. If I deal to three people there are two cards left and if I deal to five people there are two cards left. How many cards are there?”The answer to this question is difficult to find and has been discussed on many threads.Ramnath Takiar, explains it on the Quora forum, by deducing the riddle starting with the possibility ability of the remaining cards when divided between players: “When divided among 4 people, there are 3 cards left. This means that the number of lost cards could be 1.5 or 9, so we only have 3 cards left. According to this method, the number of cards available should be 52–1=51; 52–5=47; 52–9=43″”Case 1: when losing a card (available card will be 51), when 51 cards are divided among 4 people, there will be 3 remaining points (48+) 3) satisfy the given condition give. When 51 cards are dealt to three people there will be no remainder but we expect the remainder to be 2. So this cannot be the case. Case 2: When. Loss of 5 cards (existing cards will be 47) When 47 cards are dealt to 4 people, there will be a surplus of 3 (44+3) that satisfies the given condition. When 47 cards are divided among 3 people, there will be a surplus of 2 (45) +2) that satisfies the given condition. When 47 cards are divided among 5 people, 2 will be the remainder (45+2) that satisfies the given condition. So the number of lost cards is 5 and the remaining cards are 47,” he explained. Another Quora user, whose answer was similar to Takiar, explained, There are no remaining cards of 52 or 57 lost. eliminated, 42 and the next 47, 42 is eliminated because it is divisible by 3, Number 47 satisfies all conditions. Another user explained simply: “Since n, the remaining cards are divisible by both 5 and 3 to have the same balance of 2 cards: n-2 must be divisible by 15 (i.e. 5 x3). We are told that a small number of cards have been lost so the number is likely The highest output is 45 (3×15). Check: 45 + balance of 2 cards = 47, Divide by 4. Do we have 3 left over? How do you explain this riddle?
